find the angle whose supplementary angle is six times its complementary angle
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heya folk !!!!
Let x = the angle
then
90-x = the complement
180-x = the supplement
.
180-x = 6(90-x). ( according to question )
180-x = 540-6x
180+5x = 540
5x = 360
x = 72 degrees
Let x = the angle
then
90-x = the complement
180-x = the supplement
.
180-x = 6(90-x). ( according to question )
180-x = 540-6x
180+5x = 540
5x = 360
x = 72 degrees
SandeepSingh111:
true answer
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