Question

find the angles of a parallelogram ABCD in which angle A is equal to twice Angle B​

Answer 1

Answer:

Given,

angleA =twice angle B

So here in the question, they Did not say anything about the angle B

So you take that angle B as unknown (p)

So according to the question,

We know that adjacent angles in a parallelogram are supplementary.

So

p+2p=180 degrees

3p = 180 degrees

After transposition we get answer as 60 degrees

So

Angle A = 2p=2×p=2×60=180 degrees

Angle B = p =60 degrees

So we know that opposite angles of a parallelogram are equal So

Angle C =angle B=60 degrees

Angle D = angle A =180 degrees

So now the four angles are

angleA =180 degrees

angle B = 60 degrees

Angle C = 60 degrees

angle D = 180 degrees.

That's it answer is completed

Answer 2

Let the angle A be x

It is given that angle B is twice of angle A

Therefore, angle B = 2x

As we know that the sum of adjacent angles of parallelogram is 180

So,

Angle A +angleB=180

x + 2x=180

3x=180

=》x=180/3

=》x=60

Therefore, angle A =60

Angle B =2 (60)

=120