find the answer for the integral question
∫dx/xlogx
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hich is a special function known as the integral logarithm.
It can also be represented as -
∫1log(x)dx=∫1log(x)dx=
Let t=log(x)t=log(x) which can also be written as et=xet=x
Therefore on differentiating t=log(x)t=log(x)on both sides we get,
dt=1xdxdt=1xdx
or, dx=xdt→dx=etdtdx=xdt→dx=etdt
∫1log(x)dx=∫ettdt∫1log(x)dx=∫ettdt
which gives Ei(t)+cEi(t)+c
i.e Ei(log(x))+cEi(log(x))+c
Here EiEi is an exponential integral.
It can also be represented as -
∫1log(x)dx=∫1log(x)dx=
Let t=log(x)t=log(x) which can also be written as et=xet=x
Therefore on differentiating t=log(x)t=log(x)on both sides we get,
dt=1xdxdt=1xdx
or, dx=xdt→dx=etdtdx=xdt→dx=etdt
∫1log(x)dx=∫ettdt∫1log(x)dx=∫ettdt
which gives Ei(t)+cEi(t)+c
i.e Ei(log(x))+cEi(log(x))+c
Here EiEi is an exponential integral.
MilanElizabeth:
answer given is log(logx)+c
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Answer is log(log x) + c
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