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Prove that TriangleABD is congurent to TraingleACD
In TriangleABD and ACD
AD=AD(Common)
AB=AC(Isosceles Triangle)
And AngleDAB = AngleDAC (Since AD Is the angle bisector)
So TraingleACD is congurent to TraingleABD
Therefore BD = CD (CPCT)
Therefore D is the mid point of BC
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Using Angular Bisectors Theorem.
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