Math, asked by srijareddy12345, 1 year ago

find the answers for given question

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Answered by hukam0685
2

 {x}^{3}  + 3 {x}^{2}  + 3x + 1 \\ 1)x + 1 \\ x =  - 1 \\ ( { - 1)}^{3}  + 3( { - 1)}^{2}  + 3( - 1) + 1 \\  =  - 1 + 3 - 3 + 1 \\  = 0 \\ 2)x -  \frac{1}{2}  \\ x =  \frac{1}{2}  \\ (  { \frac{1}{2} )}^{3}  + 3 {( \frac{1}{2} )}^{2}  + 3 (\frac{1}{2})  + 1 \\   = \frac{1}{8}  +  \frac{3}{4}  +  \frac{3}{2}  + 1 \\  =  \frac{1 + 6 + 12 + 8}{8}  \\  =  \frac{27}{8}  \:  \:  \: ans \\ 3)x = 1 \\  =  {(1)}^{3}  + 3 {(1)}^{2}  + 3(1) + 1 \\  = 1 + 3 + 3 + 1 \\  = 8 \:  \: ans \\ 4)x + \pi \\ x =  - \pi \\  -  {(\pi)}^{3}  + 3 {(\pi)}^{2}  + 3\pi + 1 \:  \:  \: ans \\ 5) \: 5 + 2x \\ x =  \frac{ - 5}{2}   \\ =   \frac{ - 125}{8}  +  \frac{75}{4}   -  \frac{15}{2}  + 1 \\  =  \frac{ - 125 + 150 - 60 + 8}{8}   \\ =  \frac{27}{8}
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