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area of shaded region = area of TRAPEZIUM - area of SECTOR
= 1/2 * H * (SUM OF PARALLEL SIDES) - Ф πr² / 360°
in Δ BFC
sin 60° = BF/BC
√3/2 = BF / 7
BF = 7√3/2
== 1/2 * 7√3/2 * (7+11) - 60° * 22*7*7 / 7*360
= 1/2 * 7√3 / 2 * 18 - 77/3
=63√3 / 2 - 77/3
= 63*1.732 / 2 - 77/3
= 54.558 - 25.67
= 28.89 cm ² approx.
= 1/2 * H * (SUM OF PARALLEL SIDES) - Ф πr² / 360°
in Δ BFC
sin 60° = BF/BC
√3/2 = BF / 7
BF = 7√3/2
== 1/2 * 7√3/2 * (7+11) - 60° * 22*7*7 / 7*360
= 1/2 * 7√3 / 2 * 18 - 77/3
=63√3 / 2 - 77/3
= 63*1.732 / 2 - 77/3
= 54.558 - 25.67
= 28.89 cm ² approx.
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