Question

find the Anti derivatives or integral of cos3x by the method of inspection 

Answer 1

HELLO DEAR,

the anti derivatives of cos3x is a function of x whose derivative is cos3x.

we know:- $\bold{\frac{d}{dx}sin3x = 3cos3x}$

$\bold{\Rightarrow cos 3x = \frac{1}{3}\frac{d}{dx}(sin3x)}$

$\therefore \bold{cos3x = \frac{d}{dx}(\frac{1}{3}sin3x)}$.

HENCE, the Anti derivatives of cos3x = 1/3(sin3x).

I HOPE ITS HELP YOU DEAR,
THANKS