integration of (4e^{3x} + 1).dx
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HELLO DEAR,
GIVEN function is ∫(4e^{3x} + 1).dx
we may write , ∫(4e^{3x} + 1).dx as ∫4e^{3x}dx + ∫dx
So, ∫4e^{3x}dx + ∫dx
⇒ 4e^{3x}/3 + x + c
HENCE, the integration of (4e^{3x} + 1) is (4e^{3x}\3 + x) + c.
I HOPE ITS HELP YOU DEAR,
THANKS
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