Question

integration of (4e^{3x} + 1).dx

Answer 1

HELLO DEAR,

GIVEN function is ∫(4e^{3x} + 1).dx

we may write , ∫(4e^{3x} + 1).dx as ∫4e^{3x}dx + ∫dx

So, ∫4e^{3x}dx + ∫dx

⇒ 4e^{3x}/3 + x + c

HENCE, the integration of (4e^{3x} + 1) is (4e^{3x}\3 + x) + c.

I HOPE ITS HELP YOU DEAR,
THANKS