integration of [√x - 1/√x]².dx
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HELLO DEAR,
given function is ∫(√x - 1/√x)².dx
⇒ ∫(x + 1/x - 2).dx
⇒ ∫x.dx + ∫1/x.dx - 2∫dx
⇒x²/2 + log|x| - 2x + c
hence, the integration of [√x - 1/√x]² is (x²/2 + log|x| - 2x) + c.
I HOPE ITS HELP YOU DEAR,
THANKS
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