Math, asked by BrainlyHelper, 1 year ago

integration of  [√x - 1/√x]².dx

Answers

Answered by shashankavsthi
24
Hope it will help you.
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Answered by rohitkumargupta
33

HELLO DEAR,

given function is ∫(√x - 1/√x)².dx

⇒ ∫(x + 1/x - 2).dx

⇒ ∫x.dx + ∫1/x.dx - 2∫dx

⇒x²/2 + log|x| - 2x + c


hence, the integration of [√x - 1/√x]² is (x²/2 + log|x| - 2x) + c.


I HOPE ITS HELP YOU DEAR,
THANKS

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