Question

find the Anti derivatives or integral of  sin2x - 4e^{3x}the method of inspection. 

Answer 1

HELLO DEAR,

the anti derivatives of sin2x - 4e^{3x} is a function of x whose derivative is sin2x - 4e^{3x}

nos, ∫(sin2x - 4e^3x)dx

∫(sin2x).dx - ∫(4e^{3x}).dx

-1/2cos2x - 4e^{3x}/3

Hence, the Anti derivatives of (sin2x - 4e^{3x}) = -(1/2cos2x + 4e^{3x}/3)

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Answer:

thre anti derivative of sin 2x - 4e^ 3x

Step-by-step explanation:

it is known that,

d/dx (-1/2 cos 2x -1/4 e^3x ) = sin 2x -4e^3x