Question

find the Anti derivatives or integral of sin2x by  the method of inspection.

Answer 1

HELLO DEAR,

the anti derivatives of sin2x is a function of x whose derivative is sin2x.

we know $\bold{d(cos2x)/dx = -2sin2x}$

$\Rightarrow \bold{sin2x = \frac{-1}{2}\frac{d}{dx}(cos2x)}$

$\therefore \bold{sin2x = \frac{d}{dx}(\frac{-1}{2}cos2x)}$

I HOPE ITS HELP YOU DEAR,
THANKS