Question

find the AP if the 10th term is 46 and the sum of the 5th and 7th term is 52

Answer 1

In an A. P, there is a first term (a) and a common difference (d) ........
first term =a
second term=a+d
third term =a+2d
.......and so on
10th term=a+9d=46
5th term=a+4d
7th term=a+6d
sum of fifth and seventh term=52
a+4d+a+6d=52
2a+10d=52
2(a+5d)=52
2a+10d-(a+9d) =a+d=52-46=6
a+9d-(a+d)=46-6=40
8d=40
d=5
a=1

Then the A. P = 1,6,11,16.......

Here is your answer...
Hope u understand.. ☺☺☺
plz mark it as brainliest.....

Answer 2

Answer:

a+9d=46 1

a+4d+a+6d=52

2a+10d=52

a+5d=26 2

Subtract 1&2,we qet,

a+9d-a-5d=46-26

4d=20

d=5

Put value of "d" in 1

a+45=46

a=1