find the area and perimeter of a rectangle whose length and breadth are in the ratio 63 ratio 16 and diagonal is equal to 130 centimetre
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let l and B be 63x and 16x
130^2 = 3969x^2+ 256x^2
16900 = 4225 x^2
x^2= 16900/4225 = 4
x = 2
l = 63x = 126cm
B = 16x = 32 cm
perimeter= 2(l+B) = 316cm
area = 126*32 = 4032sq.cm
130^2 = 3969x^2+ 256x^2
16900 = 4225 x^2
x^2= 16900/4225 = 4
x = 2
l = 63x = 126cm
B = 16x = 32 cm
perimeter= 2(l+B) = 316cm
area = 126*32 = 4032sq.cm
shubham412:
sorry but your answer is wrong
as per your question solution is correct .. hope i have posted correct question
hope u hv posted correct question
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