Question

find the area and perimeter of a square plot of land the length of diagonal is 14 m give your answer correct to 2 decimal of

Answer 1

The above problem can be solved by using Pythagoras theorem

Let the side of the square plot be $x$
Since it is a square base is equal to perpendicular p=b
$p^{2}+ b^{2}=h^{2} \\ p=b=a \\ h=14 \\ a^{2} + a^{2}=14^{2} \\ 2 a^{2}=196 \\ a= \sqrt{ \frac{196}{2} }= \sqrt{98}$

Area = [tex]a*a \\ \sqrt{96}* \sqrt{96} =96 [/tex]

Perimeter = $4*a \\ =39.19$

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