find the area of a irregular quadrilateral With measures 25 feet,43 feet, 57.4 feet, 62.10 feet. Wrong answer will be reported and right answer will be marked as brainliest. 25 point.
Answers
Answer:
I have solved for a general question with general method....u can apply procedure for u r question....
Step-by-step explanation:
The Area of any Irregular Quadrilateral
A plane figure bounded by four straight line segments is called an irregular quadrilateral. The area of any irregular quadrilateral can be calculated by dividing it into triangles.
Example:
Find the area of a quadrilateral ABCD whose sides are 9 m, 40 m, 28 m and 15 m respectively and the angle between the first two sides is a right angle.
Solution:
irregular-quadrilateral-01
From the figure we notice that ABD is a right-angled triangle, in which AB=40 m, AD=9 m. Also
BD2=AB2+AD2BD2=402+92BD=402+92−−−−−−−√=1681−−−−√=41
Now, the area of ΔABD=12×40×9=180 m
In ΔBCD, BD=a=41 m, DC=b=28 m, CB=c=15 m
∴s=a+b+c2=41+28+152=42 m
Now,
AreaofΔBCD=s(s–a)(s–b)(s–c)−−−−−−−−−−−−−−√AreaofΔBCD=42(42–41)(42–28)(42–15)−−−−−−−−−−−−−−−−−−−−−√=42×14×27−−−−−−−−−−√=126sqm
The area of the quadrilateral ABCD= area of ΔABD +area of ΔBCD
The area of the quadrilateral ABCD =(180+126)=306 square meters.
feel free to ask me if you have any doubt......
