find the area of a quadrilateral ABCD whose diagonal AC is 25cm long and the lengths of perpendiculars from opposite vertices B and D on AC are BE = 3.6cm and DF =2.4cm. [Hint : Area of quadrilateral ABCD = (area of ∆ABC) + (area of ∆ACD) = (1/2 * AC * BE) + (1/2 * AC * DF)]
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Answer is 75cm........
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