Question

find the area of a rectangle whose length is twice its breadth is 5x​

Answer 1

Let the breadth of rectangle be x

then, the length of rectangle will be 2x

So,

Area of rectangle = (2x) × (x) → 2x² sq. units

Answer 2

Given:

Breadth of rectangle = $5x$ units

Length of rectangle = 2 × breadth of rectangle

To find:

Area of rectangle.

Solution:

Let length of a rectangle be $l$ and breadth of a rectangle be $b$. Then, its area $(A)$ is the space occupied by rectangle. The formula of area of a rectangle is given by:

$Area=length*breadth$

$A=l*b$

Here, the breadth of the rectangle is given as $5x$ and its length is twice its breadth, i.e.,

$l=2b$

$l=2*5x=10x$

Let length of the rectangle be $x$ units.

Then area is given by:

$A=l*b$

$A=x*10x$

$A=10x^{2}$ sq. units

Hence, area of a rectangle is $10x^{2}$ sq.units.

$10x^{2}$ sq.units is the area of a rectangle whose length is twice its breadth and whose breadth is $5x$.