Question

find the area of a rectangular plot one side of which is 48 M and its diagonal is 50 m

Answer 1

diagonal =50m 

length=48m 

diagonal=√Lsquare +Bsquare 

a/q=√48²+B² =50m 

=√2304+breadth² =50 

2304+B²=2500 

B ² =2500-2304
 
B² =169 .

B=√169 

B=13m 

now,area=l×b .

=48×13 .

=624 m²

Answer 2

Heyyyy mate..


Here is your answer..

according to attachment.

given, Diagonal AD=50m

and one side = let CD=48 m

In triangle ACD this is a right angle triangle

we know that Pythagoras theorem

AD^²= AC^²+CD^²

50^²=AC^²+48^²

AC^²= 50^²-48^²

AC=√2500-2304=√196

AC=14m

area of rectangular plot = length× Breadth

48×14=672m^²

hope it help you