Question

Find the area of a rhombus who's diagnols measure 13.2 and 15.6


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Answer 1

Given:-

• Diagonals of a rhombus is 13.2 and 15.6.

To find:-

• Area of a rhombus.

Solution:-

Here,

• D1 = 13.2
• D2 = 15.6

→ Area = ½ × D1 × D2

→ Area = ½ × 13.2 × 15.6

→ Area = ½ × 205.92

→ Area = 102.96 sq.units

Hence,

• the area of a rhombus is 102.96 sq.units.

More Formulas:-

→ Area of rectangle = length × breadth sq.units

→ Perimeter of square = 4 × side units

→ Area of square = side × side sq.units

→ Perimeter of circle = 2πr units

→ Area of circle = πr² sq.units

→ Perimeter of parallelogram = 2 × (a + b) units

→ Area of parallelogram = base × height sq.units

→ Perimeter of rhombus = 4 × side units

→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units

→ Perimeter of equilateral triangle = 3 × side units

→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units

→ Perimeter of trapezoid = (Sum of all sides) units

→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units

Answer 2

Given : Diagonals of a rhombus are 13.2 units and 15.6 units respectively.

To Find : Area of the rhombus

⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀____________________

For finding area of the rhombus formula is given by :

$\: \:$

$\star \: \underline{\boxed{\sf\purple{Area \: of \: a \: rhombus \: = \frac{1}{2} \times d1 \times d2}}}$

$\:$

☯︎ Where d1 denotes first diagonal and d2 denotes second diagonal

$\:$

$\underline{\mathfrak{substituting \: the \: values : }}$

$\:$

$\sf:\implies \: Area_{(rhombus)} \: = \dfrac{1}{2} \times d1 \times d2 \\ \\ \\ \sf:\implies \: Area_{(rhombus)} = \frac{1}{2} \times 13.2 \times 15.6 \\ \\ \\ \sf:\implies \: Area_{(rhombus)} \: = \frac{1}{\cancel{2}} \times \cancel{13.2} \times 15.6 \\ \\ \\ \sf:\implies \: Area_{(rhombus)} \: = 6.6 \times 15.6 \\ \\ \\ \sf:\implies \: Area_{(rhombus)} \: \underline{\boxed{\mathfrak\purple{102.96 \: sq.units}}}\bigstar \\ \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: area \: of \: the \: rhombus \: is \: \bold{102.96 \: sq.units}}}$