Question

find the area of a rhombus whose side is 8 cm and whose altitude is 5 cm if one of its diagonal is 10 cm find the length of the Other diagonal

Answer 1

Answer: 6cm

Step-by-step explanation:

Solution:-

Area of the rhombus = Side × Length of the altitude 

= 5*4.8

= 24 sq cm 

Now,

Let the length of the other diagonal = x

It is known that the area of a rhombus is half the product of its diagonals. 

∴ (1/2) × 8 × x = 24

⇒ 4x = 24

⇒ x = 6 cm

The length of the other diagonal is 6 cm.

Answer.

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =8×5=40

Since, Area of rhombus is 40 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=10

Let length of other diagonal =$d_2$

After substituting the values, we get

$40=\frac{1}{2}×10×d_2$

$40=5×d_2$

$5×d_2=40$

$d_2=\frac{40}{5}$

$d_2=8$

Hence, length of other diagonal is 8 cm.