find the area of a segment of a circle of radius 21 cm if the arc of the segment has a measure of 60°.(take √3 = 1.73)
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answer is 161.07cmsq.
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Answer:
Area of sector OAB =X\360°×πr²
=60/360×22/7×21×21
231
here, the triangle ABC is an equilateral triangle, so the area of triangle OAB=√3/4r²=√3/4×21×21
190.73
therefore area of shaded region =231-190.73
=40.27
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