find the area of a square inscribed in a circle of radius x cm
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AB diagonal divides angleACB INTO half
sin 45 = 1/2 = BC/2x
2x = 2BC
x = BC
side of a square = radius of circle
area of square is x^2cm^2.
sin 45 = 1/2 = BC/2x
2x = 2BC
x = BC
side of a square = radius of circle
area of square is x^2cm^2.
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aman47569:
can you just write the main answer
plz.
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