find the area of a square whose diagonal is 5 under root 2 cm
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the area of square is 25cm square
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By pythagorus theorem
(AC)^2=(AB)^2+(BC)^2
Let AB=BC=x Because sides are equal
(5under root 2)^2=(x)^2+(x)^2
25×2=2x^2
50/2=x^2
25=x^2
5=x
area of square = (5)^2=25
(AC)^2=(AB)^2+(BC)^2
Let AB=BC=x Because sides are equal
(5under root 2)^2=(x)^2+(x)^2
25×2=2x^2
50/2=x^2
25=x^2
5=x
area of square = (5)^2=25
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