Question

Find the area of a trapezium if the length of it's two bases is 8.8 m and 12.9 m respectively and the prependicular distance between two bases is 12 m.


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Answer 1

Answer:

If the two bases of the trapezium are 8.8m and 12.9m respectively, and the perpendicular distance between bases is 12m, then the area is 130.2 m

Step-by-step explanation:

Given

Length of base 1 =8.8 m

Length of base 2 = 12.9 m

Perpendicular distance/height = 12m

Area of trapezium given = $\frac{1}{2}height ( base1+ base 2)\\\\= \frac{1}{2} *12*(8.8+12.9)\\\\= 6 * 21.7\\\\= 130.2m$

So the area os 130.2 m

Answer 2

Answer:

Formula for the area of Trapezium is (a+b)/2 * h

Where a and b are parallel sides (also the base in this question)

Lets take a = 8.8 m

and b =  12.9 m

Distance = h = height

So,

h = 12 m

Area = 1/2(8.8 + 12.9)*12

Area = 130.2 m^2