Question

Find the area of a trapezium whose lengths of its parallel sides are 19m and 24m
respectively and distance between them is 14m.​

Answer 1

The area of a trapezium is

$\frac{1}{2}(a + b)h$

Here, the sides (a and b) are 19m and 24m. the height (h) is 14m.

So using the formula given above, the area of trapezium is:

$\frac{1}{2} \times (19 + 14) \times14$

=

$\frac{1}{2} \times 33 \times 14$

=

$231m$

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