Question

Find the area of a triangle two sides of which
are 12cm and 10cm and the perimeter is 30cm.​

Answer 1

Answer:

960

Step-by-step explanation:

first add 12cm+10cm=32cm.

Area=length × breadth.

=32cm×30cm

=960cm.

Area of the triangle of two sode is 960cm.

Answer 2

Answer:

15√7

Step-by-step explanation:

3rd side = 30-(12+10) = 8

S = 30/2 = 15

Area of ABC =

$\sqrt{15(15 - 8)(15 - 12)(15 - 10)}$

$\sqrt{15 \times 7 \times 3 \times 5}$

Ans = 15√7