Question

find the area of a triangle two sides of which are 13cm and 8 CM and perimeter is 32cm

Answer 1

32-24=8

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Answer 2

hiii!!!

here's ur answer..

let the three sides of the triangle be a, b and c

given the perimeter of the triangle = 32cm

therefore a + b + c = 32cm

==> 13 + 8 + c = 32cm

==> 21 + c = 32cm

==> c = 32 - 21

==> c = 11

if perimeter of the triangle is 32cm then it's s (semi-perimeter) is = 32/2 = 16cm.

area of the triangle by heron's formula

 $= \sqrt{s(s-a)(s-b)(s-c)} \\ \\ = \sqrt{16(16-13)(16-8)(16-11)} \\ \\ = \sqrt{16*3*8*5} \\ \\ = 8\sqrt{30}cm ^{2}$

hope this helps...!!