Find the area of a triangle, two sides of which are 8 and 11and perimeter is 32
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Given,
AB= 8 units
BC= 11 units
Perimeter= 32 units
To find,
Area of the triangle
ATQ,
Perimeter= AB + BC + AC
32= 8+11+AC
32-19= AC
AC= 13 units
Now,
By Heron's formula:-
Area= √[s(s-a)(s-b)(s-c)]
So,
s=32/2=16 units
Now,
Area= √[16(16-8)(16-11)(16-13)
= √[16*8*5*3]
= √1920
= 43.817 units
= 44 units. [Approx]
Hope this helps you!
AB= 8 units
BC= 11 units
Perimeter= 32 units
To find,
Area of the triangle
ATQ,
Perimeter= AB + BC + AC
32= 8+11+AC
32-19= AC
AC= 13 units
Now,
By Heron's formula:-
Area= √[s(s-a)(s-b)(s-c)]
So,
s=32/2=16 units
Now,
Area= √[16(16-8)(16-11)(16-13)
= √[16*8*5*3]
= √1920
= 43.817 units
= 44 units. [Approx]
Hope this helps you!
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