Question

find the area of a triangle which has a height of 3 cm and breadth 4 cm​

Answer 1

• Given

• Height = 3 cm
• Breadth = 4cm

• To find

• Area of triangle

• Solution

$\underline{\boxed{\sf{Area~of~triangle~= \dfrac{1}{2} \times base \times height}}}$

Substitute the given values.

⇛ 1/2 × 3 × 4

⇛ 6 cm²

$\underline{\boxed{\sf{Area~of~triangle~= 6~cm^2}}}$

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Know more -

There three types of triangle -

• Equilateral triangle
• Isosceles triangle
• Scalene triangle 

Equilateral triangle -

• In this all three sides are equal.

Area of equilateral triangle -

• ↬ $\sf{\dfrac{\sqrt{3}}{4}a^2}$

Perimeter of equilateral triangle -

• ↬ 3a

where,

a = side of triangle

Isosceles  triangle -

• In this two sides of triangle are equal.

Area of isosceles triangle -

• ↬ $\sf{\dfrac{1}{2} \times base \times height}$

Perimeter of isosceles triangle -

• ↬ 2a + b

Scalene triangle -

• In this no side is equal.

Area of scalene triangle -

• ↬ Heron's formula = $\sf{\sqrt{s(s - a)(s - b)(s - c)}}$

Perimeter of scalene triangle -

• ↬ Perimeter = Sum of all three sides

Answer 2

Qᴜᴇsᴛɪᴏɴ:-

➨ғɪɴᴅ ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ ᴡʜɪᴄʜ ʜᴀs ᴀ ʜᴇɪɢʜᴛ ᴏғ 3ᴄᴍ ᴀɴᴅ ʙʀᴇᴀᴅᴛʜ 4ᴄᴍ.

Aɴsᴡᴇʀ:-

➨ɢɪᴠᴇɴ:-

ʜᴇɪɢʜᴛ ɪs 3ᴄᴍ

ʙʀᴇᴀᴅᴛʜ ɪs 4ᴄᴍ

➨Tᴏ ғɪɴᴅ:-

ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ

➨sᴏʟᴜᴛɪᴏɴ:-

ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ= ½×ʙᴀsᴇ×ʜᴇɪɢʜᴛ

=½×4×3

= 2×3

= 6ᴄᴍ²

sᴏ ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ ɪs 6ᴄᴍ².

➨Exᴛʀᴀ sʜᴏᴛs:-

ᴛʜᴇʀᴇ ᴀʀᴇ ᴛʜʀᴇᴇ ᴛʏᴘᴇs ᴏғ ᴛʀɪᴀɴɢʟᴇ:-

➨ᴇǫᴜɪʟᴀᴛᴇʀᴀʟ ᴛʀɪᴀɴɢʟᴇ

➨ɪsᴏsᴄᴇʟᴇs ᴛʀɪᴀɴɢʟᴇ

➨sᴄᴀʟᴇɴᴇ ᴛʀɪᴀɴɢʟᴇ

ᴀʀᴇᴀ ᴏғ ᴇǫᴜɪʟᴀᴛᴇʀᴀʟ ᴛʀɪᴀɴɢʟᴇ- √3/4ᴀ²

ᴀʀᴇᴀ ᴏғ ɪsᴏsᴄᴇʟᴇs ᴛʀɪᴀɴɢʟᴇ- 1/2×ʙ×ʜ

ᴀʀᴇᴀ ᴏғ sᴄᴀʟᴇɴᴇ ᴛʀɪᴀɴɢʟᴇ-√s(s-ᴀ)(s-ʙ)(s-ᴄ).

ᴀɴᴅ ᴀʟʟ ᴡᴇ ᴀʀᴇ ᴅᴏɴᴇ✔️

ʜᴏᴘᴇ ɪᴛs ʜᴇʟᴘs ᴜʜ❣️