Question

find the area of an isosceles triangle each of whose equal sides is 13 cm and base 24 centimetre

Answer 1

Heya !!!



Here,



Base (B) = 24 cm and each equal sides (A) = 13 cm




Then,



Area of an isosceles triangle = 1/4 × B ✓4A²-B²





=> 1/4 × 24 × ✓4 × (13)² - (24)²




=> 6 × ✓676 - 576



=> 6 ✓100



=> 6 × 10



=> 60 cm².



★ HOPE IT WILL HELP YOU ★

Answer 2

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$\rm \: here \: each \: equal\: side \: \: a = 13cm \: and \: base = 24cm \\ \\ \therefore \rm \: area \: of \: the \: triangle = \big({ \frac{1}{4} b. \sqrt{4a {}^{2} - b {}^{2} } } \big)cm {}^{2} \\ = \big( \frac{1}{4 } + 24 \times \sqrt{4 \times 169 - 24 \times 24} \big) cm {}^{2} \\ = 60 \: cm {}^{2}$