Question

find the area of an isosceles triangle each of whose sides measures 13 cm and whose base measures 20 cm​

Answer 1

Answer:

firstly you have to solve it by yourself

Answer 2

${\green {\boxed {\mathtt {✓verified\:answer}}}}$

Your answer

$</p><p>{\bf{\blue{\underline{Given:}}}}$

$\rm \: here \: each \: equal\: side \: \: a = 13cm \: and \: base = 20cm \\ \\ \therefore \rm \: area \: of \: the \: triangle = \big({ \frac{1}{4} b. \sqrt{4a {}^{2} - b {}^{2} } } \big)cm {}^{2} \\ = \big( \frac{1}{4 } + 20 \times \sqrt{4 \times 169 - 20 \times 20} \big) cm {}^{2} \\ = 83.07 \: cm {}^{2}$