Question

find the area of an isosceles triangle in which of the equal side measuring 30 cm and the third side is 48 cm long

Answer 1

Let a = 30cm, b= 30cm and c = 48cm

s = (30 + 30 + 48) 2

= 54cm

Now apply heron's formula

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{54(54 - 30)(54 - 30)(54 - 48)}$

$\sqrt{54 \times 24 \times 24 \times 6}$