Question

find the area of an isosceles triangle whose base is 8 cm and length of each equal side is 5 cm

Answer 1

Answer: The area of an  isosceles triangle is 12cm² whose base is 8cm and length of each equal side is 5cm.

Step-by-step explanation:

Equal sides of an isosceles triangle = 5cm

Base of an isosceles triangle= 16cm

Here we will use Heron's formula to find the area of this triangle

Here, area of triangle according to formula of Heron's = √s (s - a) (s - b) (s - c)

where,

a = 5cm

b = 5cm

c = 8cm

To find s, we will divide sum of a, b and c with 2

s =( a+b+c)/2

s = (5+ 5 + 8)/2

s = 18/2

s = 9

Thus, Area = √s (s - a) (s - b) (s - c)

Area = √9 (9 - 5) (9 - 5) (9 - 8)

Area = √9 × 4 × 4 × 1

Area = √3 × 3 × 2 × 2 × 2 × 2

Area = 3 × 2 × 2

Area = 12cm²

Hence, the area of an  isosceles triangle is 12cm² whose base is 8cm and length of each equal side is 5cm.

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Answer 2

Answer:

base = 8cm

area = 12cm²

Step-by-step explanation:

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