find the area of corridors whose side is 3m 3m 10m 7m
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Answered by
3
total surface area= 2 (LB + LH + BH)
= 2×(3×10+3×7+7×10)
= 2×( 30+21 + 70)
= 2×(121)
= 242M2
= 2×(3×10+3×7+7×10)
= 2×( 30+21 + 70)
= 2×(121)
= 242M2
Answered by
17
T.S.A of corridors = 2[(3×10) + (10×7) + (7×3)]
T.S.A of corridors = 2(30 + 70 + 21)
T.S.A. of corridors = 2(121)
T.S.A of corridors =
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