Find the area of Fig15.68, in square cm, correct to one place of decimal.(Take π=22/7)
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Answer:
115cm²
Step-by-step explanation:
To find the area of the given figure.
For the square ABCD,
The side AB=10cm
Thus, Area=10×10cm²
A semicircle is attached to side BC of the square.
The diameter of semicircle=10 cm
so, the radius of semicircle=5cm
The area of semicircle of radius r is A'=1/2πr²
By substituting the value of r,
A'=1/2×22/7×5×5=39.3cm²
From the above figure, it is seen that a right angle triangle is cutoff from one side of square.
The area of right angled triangle=1/2×bh=1/2×8×6=24cm²
Now, the area of above figure is,
Now, the area of above figure is,Area=area of square+area of semicircle-area of triangle=100+39.3-24=115cm²
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thanks for the answer
Step-by-step explanation:
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