In Fig.15.69, AB and CD are two diameters of a circle perpendicular to each other and OD is the diameter of the smaller circle. If OA=7cm, find the area of the shaded region.
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Area of Shaded region =2× Area of segment BC (or Segment AC) + Area of circle with diameter DO
Since, DO=OC=BO=AO=7cm
∴ Area of segment BC = Area of quadrant BOC − Area of △ BOC={(π×7×7)/4-1/2×7×7)}
=14cm²
Step-by-step explanation:
Area of circle with diameter OD =π×3.5×3.5
=38.5cm ²
∴ Area of Shaded region =2×14+38.5=66.5cm ²
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