Find the area of isosceles triangle whose one side is 10cm greater than its equal side and its perimeter is 100cm (Take root 5 is 2.23
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in isosceles triangle , perpendicular bisects the triangle into two equal halves. let x be side of the triangle then the greater side is x+10 base
now
x+x+x+10=100 perimeter
x=30
draw a perpendicular the base
as mentioned above it divided triangle into two halves . now consider the small triangle as right angle triangle with base 30+10/2=20and hypotenuse as 30 solve for height u will get 10√5
apply area formula to get =1/2*10√5*40= 446 base is of original triangle
now
x+x+x+10=100 perimeter
x=30
draw a perpendicular the base
as mentioned above it divided triangle into two halves . now consider the small triangle as right angle triangle with base 30+10/2=20and hypotenuse as 30 solve for height u will get 10√5
apply area formula to get =1/2*10√5*40= 446 base is of original triangle
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