Find the area of parallelogram ABCD in which AB=14cm ,BC=10cm and AC=16cm.
(given ,√3=1.73)
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Answer:
ab =cd=14cm(in parallelogram opposite
BC=ad=10cm. sides are equal)
ar(ABC)=ar(ACD)(same base lies b/w same parallel therefore it's areas are equal)
ar(ABCD)=ar(ABC)+ar(ACD)
=2ar(ABC)
ar(ABCD)=b*h
=14*10=140
Step-by-step explanation:
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1
Answer:
GdgdysVshsVd VG ssugshshhshs
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