Question

find the area of quadrilateral whose one diagonal is 20 cm long and the perpendicular to its diagonal from the other vertex are length 9 cm and 15 CM

Answer 1

Answer: The area of quadrilateral is 240 cm².

Step-by-step explanation:

Since we have given that

Diagonal of the quadrilateral = 20 cm

Perpendicular to its diagonal from the other vertex are (h₁=) 9 cm and (h₂=) 15 cm.

Area of the quadrilateral is given by

$\frac{1}{2}\times (h_1+h_2)\times d\\\\=\frac{1}{2}\times (15+9)\times 20\\\\=\frac{1}{2}\times 24\times 20\\\\=240\ cm^2$

Hence, the area of quadrilateral is 240 cm².

Answer 2

Step-by-step explanation:

Answer: The area of quadrilateral is 240 cm².

Step-by-step explanation:

Since we have given that

Diagonal of the quadrilateral = 20 cm

Perpendicular to its diagonal from the other vertex are (h₁=) 9 cm and (h₂=) 15 cm.

Area of the quadrilateral is given by

\begin{gathered}\frac{1}{2}\times (h_1+h_2)\times d\\\\=\frac{1}{2}\times (15+9)\times 20\\\\=\frac{1}{2}\times 24\times 20\\\\=240\ cm^2\end{gathered}

2

1

×(h

1

+h

2

)×d

=

2

1

×(15+9)×20

=

2

1

×24×20

=240 cm

2

Hence, the area of quadrilateral is 240 cm².