Question

Find the area of rhombus whose perimeter is 80m and one of whose diagonal is 24 m

Answer 1

Area of rhombus =1/2×d1×d2
Diagonal of rhombus bisect each other at 90°
SO one digonal =24/2=12
side of rhombus =80/4=20
By phythagoreas theorem
(20)^2 = 12^2+another side ^2
400=144+another side ^2
root 400-144 = another side
=16
Now full length =16×2=32
Area of rhombus =1/2×24×32
Ans: 384m^2