Question

Find the area of shaded region where arc drawn with centre A B C D intersect in pair at mid point P Q R S of side AB BC CD DA respectively of square of side 12 cm

Answer 1

First find the area of the square that is side square y get 12*12=144cmsq.
Then find area of the four quadrants
Subtract that from area of square you will get ur answer

By the way u have not posted any figure so that's why I can't solve properly

Answer 2

Area of the shaded region = Area of the square ABCD - 4 × Area of a quadrant or a circle with r = 6cm

$\longrightarrow$$\sf{12cm \times 12cm - \times \frac{1}{4} = 3.14 \times 6cm \times 6cm}$

$\longrightarrow$$\sf{(144 - 113.04) {cm}^{2} }$

$\longrightarrow$${\boxed{\sf{\red{{30.96cm}^{2}}}}}$