Find the area of the blades of magnetic compass shown in fig.12.27.(take √11=3.32)
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The diagram is not given. I make one diagram. Hope it is right. But for the dimensions, I have two possibilities... of the size of magnetic compass needle or blade. A magnetic compass needle is in the shape of a Rhombus.
Figure1:
side = AB = 5 cm. Diagonal BD = 1 cm. BO = 0.50 cm
Using Pythagoras theorem:
AO² = AB² - OB² = 25 - 1/4 = 99/4
AO = 3 √11 /2 = 3 * 3.32 /4 = 2.49 cm
Diagonal AC = 2 * AO = 4.98 cm
BD = 1 cm
Area of the blade = 1/2 * AC * BD = 2.49 cm²
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Figure 2:
AC = 10 cm AO = 5 cm AB = 6 cm
OB² = AB² - AO² = 6² - 5² = 11
OB = √11 = 3.32 cm
Diagonals BD = 2 * OB = 6.64 cm
AC = 10 cm
Area ABCD = 1/2 * AC * BD = 33.2 cm²
Figure1:
side = AB = 5 cm. Diagonal BD = 1 cm. BO = 0.50 cm
Using Pythagoras theorem:
AO² = AB² - OB² = 25 - 1/4 = 99/4
AO = 3 √11 /2 = 3 * 3.32 /4 = 2.49 cm
Diagonal AC = 2 * AO = 4.98 cm
BD = 1 cm
Area of the blade = 1/2 * AC * BD = 2.49 cm²
======
Figure 2:
AC = 10 cm AO = 5 cm AB = 6 cm
OB² = AB² - AO² = 6² - 5² = 11
OB = √11 = 3.32 cm
Diagonals BD = 2 * OB = 6.64 cm
AC = 10 cm
Area ABCD = 1/2 * AC * BD = 33.2 cm²
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kvnmurty:
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