Find the area of the cardboard required to make an open box of length 28 cm , breadth 50 cm and height 20 cm
Answers
Answered by
55
hey...
if the box is OPENED then we LSA OF CUBOID should be applied here.
AREA = LSA(area of four walls)+ area of base
AREA= 2 ( l + b ) h + l × b
= 2 ( 28 + 50 ) 20 + 28 × 50
= 2 × 78 × 20 + 28 × 50
= 3120 cm^2. + 1400 cm^2
= 4520cm^2
if the box is OPENED then we LSA OF CUBOID should be applied here.
AREA = LSA(area of four walls)+ area of base
AREA= 2 ( l + b ) h + l × b
= 2 ( 28 + 50 ) 20 + 28 × 50
= 2 × 78 × 20 + 28 × 50
= 3120 cm^2. + 1400 cm^2
= 4520cm^2
Anonymous:
but it will be 1400 not 1500
Answered by
13
here's ur answer frnd....
we have to find the area to make a open box. so we will use the formula=CSA+1base
CSA+1base=2h(l+b)+lb
=2×20(28+50)+(28×50)
=40×78+1400
=3120+1400
=4520cm²
hence final answer is 4520cm² of cardboard is required.
hope this helps u frnd...
^_^
we have to find the area to make a open box. so we will use the formula=CSA+1base
CSA+1base=2h(l+b)+lb
=2×20(28+50)+(28×50)
=40×78+1400
=3120+1400
=4520cm²
hence final answer is 4520cm² of cardboard is required.
hope this helps u frnd...
^_^
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