Find the area of the flower bed (rectangle with semicircular ends)
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Answered by
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GIVEN :
Length of a rectangle = 44 cm
Breadth of a rectangle = 16 cm
Diameter of circle = Breadth of a rectangle = 16 cm
Radius of Semicircle = diameter/2 = 16/2 = 8 cm
AREA OF RECTANGLE = length X breadth= 44 × 16 = 704 cm²
AREA OF 2 SEMICIRCLE= 2 ×½ πr² = (π) × 8²= 64π
Area of shaded region = Area of rectangle + Area of 2 semicircles
AREA OF SHADED REGION = 704 + 64 π) = (704 + 64π) or (704 + 64× 22/7) = 704 + 1408/7 = 704 + 201.14 = 905.14
Hence, the Area of shaded region is (704 + 64π) or 905.14 cm².
HOPE THIS WILL HELP YOU..
Length of a rectangle = 44 cm
Breadth of a rectangle = 16 cm
Diameter of circle = Breadth of a rectangle = 16 cm
Radius of Semicircle = diameter/2 = 16/2 = 8 cm
AREA OF RECTANGLE = length X breadth= 44 × 16 = 704 cm²
AREA OF 2 SEMICIRCLE= 2 ×½ πr² = (π) × 8²= 64π
Area of shaded region = Area of rectangle + Area of 2 semicircles
AREA OF SHADED REGION = 704 + 64 π) = (704 + 64π) or (704 + 64× 22/7) = 704 + 1408/7 = 704 + 201.14 = 905.14
Hence, the Area of shaded region is (704 + 64π) or 905.14 cm².
HOPE THIS WILL HELP YOU..
Answered by
9
Answer: 905.14cm^2
Step-by-step explanation:
GIVEN :
Length of a rectangle = 44 cm
Breadth of a rectangle = 16 cm
Diameter of circle = Breadth of a rectangle = 16 cm
Radius of Semicircle = diameter/2 = 16/2 = 8 cm
AREA OF RECTANGLE = length X breadth= 44 × 16 = 704 cm²
AREA OF 2 SEMICIRCLE= 2 ×½ πr² = (π) × 8²= 64π
Area of shaded region = Area of rectangle + Area of 2 semicircles
AREA OF SHADED REGION = 704 + 64 π) = (704 + 64π) or (704 + 64× 22/7) = 704 + 1408/7 = 704 + 201.14 = 905.14
Hence, the Area of shaded region is (704 + 64π) or 905.14 cm².
HOPE THIS WILL HELP YOU..
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