Question

find the area of the polygon ​

Answer 1

Answer

20+28+6+15=69

= 69-2

=67

=67×180

=12060

=12060÷2

=6030

Answer 2

$\mathtt{\underline{\blue{Given:}}}\\ \\\mathtt{DC=20\:cm}\\\mathtt{BC=15\:cm}\\\mathtt{FE=6\:cm}$

${\mathtt{\red{After\:joining\:AD\:we\:got\:a\: trapezium}}}\ \\ \mathtt{\red{named\: AFED\: and \:a \:rectangle \:named \:ABCD}} .$

$\mathtt{\underline{\blue{Area\:of\:rectangle\: -}}}$

→ $\mathtt{Length \times Breadth}$

→ $\mathtt{DC \times BC}$

→ $\mathtt{(20 \times 15)\:{cm}^{2}}$

→ $\mathtt{300 \: {cm}^{2}}$

$\mathtt{\underline{\blue{Area\:of\:Trapezium\: -}}}$$\mathtt{\frac{{b}_{1}+{b}_{2}}{2}\times H}$

$\mathtt{\underline{Height\:of\:Trapezium\: -}}$$\mathtt{28 - 20 = 8\:cm}$

$\mathtt{{B}_{1}=6\:cm}$

$\mathtt{{B}_{2}=BC=20\:cm}$

$\mathtt{\underline{\blue{Area\:of\:Trapezium\: -}}}$

→ $\mathtt{\frac{6\:cm+20\:cm}{2} \times 8\:cm}$

→ $\mathtt{\frac{26\:cm}{2} \times 8\:cm}$

→ $\mathtt{13\:cm \times 8 \:cm }$

→ $\mathtt{104\:{cm}^{2}}$

$\mathtt{\underline{\blue{Area\:of\:Polygon\: -}}}$

$\mathtt{Area \:of \:Trapezium+Area \:of\:Rectangle}$

→ $\mathtt{300\:{cm}^{2} + 104\:{cm}^{2}}$

→ $\mathtt{\huge{\pink{404\:{cm}^{2}}}}$