Math, asked by jaskaran73, 10 months ago

Find the area of the quadrilateral ABCD whose vertices A (1,1) B (7,-3) C (12,2) and D (7,21) with step by step explaination

Answers

Answered by athang003

A (1,1)
B (7,-3)
C (12,2)
D (7'21)
therefore by distance formula
d(AB) =
$\sqrt{7 - 1 {}^{2} } + - 3 - 1 {}^{2}$
$\sqrt{52}$
same way find other sides also and thus when u get all the sides justify it as a square or rectangle and by using the area formula find its area
if it appeals you please select me as brainlist plz...

jaskaran73: how

athang003: are...u can just find all sides then u justify it is a square or rectanle and if it is square then use the formula of area of square and write the answer

athang003: simple

jaskaran73: okkk

athang003: plzz....like and select as a brainlist

Previous Question

Next Question