find the area of the quadrilateral whose sides measure 9cm, 40cm, 28cm and 15cm and in which the angle between the first two sides is a right angle
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are 9cm,40cm,28cm and 15cm respectively, in consecutive order ,and angle between first two sides is 90 degree.
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In Quadrilateral ABCD
AB = 9CM
BC = 40CM
CD = 28CM
AD = 15CM
It has two triangle
Triangle ABC and Triangle ADC
In triangle ABC
Area of ABC = 1/2 × AB ×BC
= (1/2×9×40) CM²
= 180 CM²
In triangle ADC
Area of triangle ADC = 1/2×CD×AD
= (1/2×28×15) CM²
= 210 CM²
HENCE,
Area of Quadrilateral ABCD = 180 CM²+210CM²
= 390 CM²
AB = 9CM
BC = 40CM
CD = 28CM
AD = 15CM
It has two triangle
Triangle ABC and Triangle ADC
In triangle ABC
Area of ABC = 1/2 × AB ×BC
= (1/2×9×40) CM²
= 180 CM²
In triangle ADC
Area of triangle ADC = 1/2×CD×AD
= (1/2×28×15) CM²
= 210 CM²
HENCE,
Area of Quadrilateral ABCD = 180 CM²+210CM²
= 390 CM²
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