Math, asked by riajoshi13, 1 year ago

find the area of the quadrilateral whose sides measure 9cm, 40cm, 28cm and 15cm and in which the angle between the first two sides is a right angle

Answers

Answered by loveyou22
16
are 9cm,40cm,28cm and 15cm respectively, in consecutive order ,and angle between first two sides is 90 degree.
Answered by Anonymous
72
In Quadrilateral ABCD
AB = 9CM
BC = 40CM
CD = 28CM
AD = 15CM


It has two triangle
Triangle ABC and Triangle ADC

In triangle ABC

Area of ABC = 1/2 × AB ×BC
= (1/2×9×40) CM²
= 180 CM²

In triangle ADC

Area of triangle ADC = 1/2×CD×AD
= (1/2×28×15) CM²
= 210 CM²


HENCE,

Area of Quadrilateral ABCD = 180 CM²+210CM²
= 390 CM²
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