Question

find the area of the sector whose 10.5cm, with the angle 90​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$area \: of \: sector = \frac{ \alpha }{360} \times \pi {r}^{2} \\ = \frac{90}{360} \times \frac{22}{7} \times 10.5 \times 10.5$

$= \frac{1}{4} \times \: \frac{22}{7} \times 10.5 \times 10.5 \\ = \frac{11}{2} \times 1.5 \times 10.5 \\ = 86.625 \: cm {}^{2}$