find the area of the segment of a circle of radius 14 cm ,when the angle of the corresponding sector is 30°
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Area of segment = Area of segment -area of corresponding triangle
= 49-5.13
= 43.87 Sq.cm
= 49-5.13
= 43.87 Sq.cm
Answered by
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Answer:2.33
Step-by-step explanation:
Area of segment = Pi r^2/360 - 1/2 r^2 sin theta
=r^2(pi theta/360 - 1/2sin theta
=14×14(22/7×30/360-1/2×1/2)
=196(11/42-1/4)
=196(1/84)
=196/84
=2.33
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