Question

find the area of the shaded portion in each case .​

Answer 1

${\huge{\star{\underbrace{\tt{\red{Answer}}}}}}{\huge{\star}}$

$\Large{\purple{\tt{\underline{\underline{Given \ :-}}}}}$

• Length of inner rectangle = 36m
• Breadth of inner rectangle = 56m
• Length of outer rectangle = 40m
• Breadth of outer rectangle = 60m

$\Large{\green{\tt{\underline{\underline{To \ find \ :-}}}}}$

• Area of shaded portion

$\Large{\orange{\tt{\underline{\underline{Solution \ :-}}}}}$

${\tt{\bigstar \ Let \ the \ inner \ length \ and \ breadth \ be }}\\{\tt{ l_{1} \ and \ b_{1} \ respectively \ and \ outer \ length \ and }}\\{\tt{ breadth \ be \ l_{2} \ and b_{2}}}$

${\sf{Area \ of \ shaded \ portion \ = \ area \ of \ outer \ rectangle - area \ of \ inner \ rectangle}}$

${\sf{\longmapsto \ Area \ of \ shaded \ portion \ \ = \ l_{2} \ \times \ b_{2} \ - \ l_{1} \ \times \ b_{1}}}$

${\sf{\longmapsto \ Area \ of \ shaded \ portion \ = \ 60\times40 \ - \ 36\times56}}$

${\sf{\longmapsto \ Area \ of \ shaded \ portion \ = \ 2400 \ - \ 2016}}$

${\sf{\longmapsto \ Area \ of \ shaded \ portion \ = \ 384m^{2}}}$

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